Let $X$ be a topological space.
$X$ is regular if given a proper closed set $C$ in $X$ and a point $x \in X \setminus C$, then exist $A$ and $B$ disjoint open sets in $X$ such that $x \in A$ and $C \subseteq B$.
$X$ is normal if given $C$ and $D$ disjoint closed sets in $X$, then exist $A$ and $B$ disjoint open sets in $X$ such that $C \subseteq A$ and $D \subseteq B$.
Equivalently, this is known as Urysohn's Lemma, $X$ is normal if given $C$ and $D$ disjoint closed sets in $X$, then exists $f : X \rightarrow [0, 1]$ continuous function such that $C \subseteq f^{-1}(\{0\})$ and $D \subseteq f^{-1}(\{1\})$.
$X$ is completely regular if given a proper closed set $C$ in $X$ and a point $x \in X \setminus C$, then exists $f : X \rightarrow [0, 1]$ continuous function such that $C \subseteq f^{-1}(\{0\})$ and $f(x) = 1$.
$X$ is a $G_{\delta}$ space if each closed set in $X$ is a countable intersection of open sets in $X$.
I know how normality is used in the proof of Urysohn's Lemma. And, this doesn't hold for regular spaces. I also know examples of regular spaces that aren't completely regular, not even functionally Hausdorff.
The thing is that I wanted to find examples of $T_3$ (regular and $T_0$) $G_{\delta}$ spaces that aren't completely regular. However, I haven't been able to find any. Does anyone know any examples of such, or regular + $G_{\delta}$ space implies completely regular?
Note: in $\pi$-Base there are no examples of regular + $G_{\delta}$ space + $\neg$completely regular spaces, and there are no examples of regular + Countable pseudocharacter (each point is a $G_{\delta}$ set) + $\neg$completely regular spaces.