For the system of differential equations $$\dot{x} = xy - 1,$$ $$\dot{y} = x^2 - y^2$$ sketch the phase portrait of the system near the fixed points. Use the linearization theorem.
Attempt: To analyze the system near its fixed points using the linearization theorem, we first find the fixed points by setting $\dot{x} = 0$ and $\dot{y} = 0$. Solving the equations $xy - 1 = 0$ and $x^2 - y^2 = 0$ simultaneously, we obtain the fixed points $(1, 1)$ and $(-1, -1)$. Next, we linearize the system by calculating the Jacobian matrix:
$$ J = \begin{pmatrix} \frac{\partial \dot{x}}{\partial x} & \frac{\partial \dot{x}}{\partial y} \\ \frac{\partial \dot{y}}{\partial x} & \frac{\partial \dot{y}}{\partial y} \end{pmatrix} = \begin{pmatrix} y & x \\ 2x & -2y \end{pmatrix}. $$
Now that I got Jacobian, how can I sketch the phase portrait? Any ideas?