I'm trying to understand the generalized symmetric group $G(m,1,n)$. Two simplest cases are the symmetric group $G(1,1,n)$, and the hyperoctahedral group $G(2,1,n)$. The symmetric group is learned in general abstract algebra course, so it is easy. The hyperoctahedral group the signed symmetric group of permutations $w$ either of the set $\{-n,-n+1,\cdots,-1,1,2,\cdots,n\}$ such that $w(i)=-w(-i)$ for all $i$, which is a little more complicated but still not difficult to understand.
The generalized symmetric group is the wreath product $ G(m,1,n):=\mathbb{Z}_{m}\wr S_{n}$ of the cyclic group of order $m$ and the symmetric group of order $n$. The definition of wreath product looks quite more intricate. In Wikipedia, it gives the generalized symmetric group as an example:
The base of this wreath product is the $n$-fold direct product $\mathbb{Z}_m^n = \mathbb{Z}_m \cdots \mathbb{Z}_m$ of copies of $\mathbb{Z}_m$ where the action $\varphi:S_n \to \text{Aut}(\mathbb{Z}_m^n)$ of the symmetric group of degree $n$ is given by $\varphi(\sigma)(\alpha_1,..., \alpha_n) := (\alpha_{\sigma(1)},..., \alpha_{\sigma(n)})$.
It makes me more confused. I can understand how $S_n$ acts on $\mathbb{Z}_m^2$, but I don't understand the relation between the above interpretation and the definition of $G(1,1,n)$ or $G(2,1,n)$ I state at first. Could someone please illustrate $\mathbb{Z}_{m}\wr S_{n}$ in a simpler and clearer way? Or describing $G(3,1,n)=\mathbb{Z}_{3}\wr S_{n}$ also may help!