Let $X$ be a compact, Hausdorff space. Let $B(X)$ be the Banach space of bounded, Borel-measurable, complex-valued functions on $X$ under the uniform norm. Let $C(X) \subset B(X)$ be the closed subspace of continuous, complex-valued functions.
By the Riesz representation theorem, we have an isomorphism $M(X) \cong C(X)^*$ where $M(X)$ denotes the (finite) regular, complex Borel measures on $X$ under the total variation norm. The isomorphism sends $\mu \in M(X)$ to integration against $\mu$. By the Hahn-Banach theorem, the element of $C(X)^*$ corresponding to $\mu \in M(X)$ extends to an element of $B(X)^*$ with the same norm. In fact, since the functions in $B(X)$ can also be integrated against $\mu$, we have a rather canonical choice of extension. It is not difficult to see that $f \mapsto \int_X f \ d\mu$ is in $B(X)^*$ and has the same norm as its restriction to $C(X)$.
Question: Is it true that every functional in $C(X)^*$ has a unique norm-preserving extension to $B(X)^*$ (given by integration against the corresponding measure)? Or, if not, what sort of functional analysis-type statements can be made in order to single out this extension which is obviously the preferred one from a measure theory standpoint?