0
$\begingroup$

A well-posed problem is defined as here.

If that is so, then does it mean that the solution/s of any over-determined or under-determined system is NOT well-posed?

Similarly, if the solution doesn't exist of any initial value or boundary value problem, does it mean that problem is not well-posed?

Perplexed !

$\endgroup$
  • $\begingroup$ for a problem to be well-posed all the three conditions need to be satisfied $\endgroup$ – user67133 Sep 16 '13 at 2:58
2
$\begingroup$

Since it violates 1) A solution exists (A SOLUTION NEEDN'T EXIST HERE!), this problem is not well-posed.

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.