This question is a follow-on of a previous question asked some days ago which has been deleted due to its lack of precision. In fact, I found it well explained here
But, implicitly, the domain of solutions was numbers with at most two decimals.
Let me restate the question with rational numbers :
Find four rational numbers (it is the domain I am interested in) $a \le b \le c \le d$ whose product is equal to their sum, this common value being $7.11$ :
$$abcd=a+b+c+d=\frac{711}{100}$$
The solution provided, converted into fractional expressions, is :
$$\begin{cases}a&=&6/5&=&1.20\\b&=&5/4&=&1.25\\c&=&3/2&=&1.50\\d&=&79/25&=&3.16\end{cases}$$
The numbers involved aren't so surprizing because of the prime factor decompositions :
$$711=3^2 \times 79 \ \ \text{and} \ \ 100=2^2 \times 5^2.$$
Using a computer "screening" and the above decompositions, I have found another solution :
$$\begin{cases}a&=&81/100&=&0.81\\b&=&5/3&=&1.666...\\c&=&2&&\\d&=&79/30&=&2.6333...\end{cases}$$
My questions : are there other (rational) solutions and how can we find them ? Beyond that, is there some theory behind (like the theory of rational points on cubic curves) ?