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I hoped someone can help me with 3 simultaneous equations with an additional condition. I can easily solve the following 3 equations using substitution in terms of $S_1$, $S_2$ and $S_3$" $$\begin{align*} \text{Eq 1)} &\qquad& (O_{1}-1)S_1 - S_2 - S_3 &= 0.5P\\ \text{Eq 2)} && (O_{2}-1)S_2-S_1-S_3 &= 0.29P\\ \text{Eq 3)} && (O_{3}-1)S_3-S_1-S_2 &=0.21 P \end{align*}$$

However, I'm struggling to solve these same equations with an additional condition $$\text{Eq4)}\qquad S_1+S_2+S_3 = T.$$

Essentially, I want to be able to specify $T$ and calculate the values required for $S_1$, $S_2$ and $S_3$ to make Eq1 50% , Eq2 29% and Eq3 21% of the total.

$O_1$, $O_2$, & $O_3$ are known; $P$ = Eq1+Eq2+Eq3

Any advice is appreciated, thanks. (this is not homework!)

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  • $\begingroup$ @Arturo: $O_i$ are part of the coefficients I believe... $\endgroup$
    – Aryabhata
    Commented Jun 30, 2011 at 21:44
  • $\begingroup$ Adding the three equations, we see $P = -T$. $\endgroup$
    – GEdgar
    Commented Jun 30, 2011 at 21:47
  • $\begingroup$ @Aryabhata: Oh, I see! Sorry about that. That was pretty bad mangling I did there. Fixed. $\endgroup$
    – Arturo Magidin
    Commented Jun 30, 2011 at 21:50
  • $\begingroup$ Can't you just solve for $S_i$ in terms of $P$ (they will all be multiples of $P$ from equations 1-3, using matrix multiplication/inverse to give the solution). Then you can choose P so that Equation 4 is satisfied (except in exceptional singular cases). Alternatively take the P over to the other side in 1-3. P has zero coefficient in eq4, and you have a four-dimensional problem with unknowns $S_i$ and $P$ $\endgroup$
    – Mark Bennet
    Commented Jun 30, 2011 at 22:00
  • $\begingroup$ Thanks both Mark & Shai! I've been put back on the right track and used both of your suggestions. Thank you. $\endgroup$
    – user12797
    Commented Jun 30, 2011 at 23:34

2 Answers 2

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It may be worth noting that $$ O_1 S_1 - T = 0.5P $$ $$ O_2 S_2 - T = 0.29P $$ $$ O_3 S_3 - T = 0.21P. $$

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Thanks to the help from both Shai Covo and Mark Bennet I've put put back on the right track.

I thought I'd just post up the method I used.

enter image description here

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