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I have been trying very hard to find the answer to the following integral$$\int_0^\infty\frac{\sin^2x}{x^2}dx$$ given that $$\int_0^\infty\frac{\sin x\cos x}{x}dx = \frac{\pi}{4}$$

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marked as duplicate by Julian Kuelshammer, Daniel Fischer, Cameron Buie, rschwieb, Potato Sep 5 '13 at 14:57

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  • $\begingroup$ See here for general version. $\endgroup$ – Cortizol Sep 5 '13 at 14:25
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Use integration by parts (and the fact that $\sin^2x/x$ vanishes for $ x \rightarrow 0$ and $x\rightarrow\infty$) $$\int_0^\infty\frac{\sin^2x}{x^2}dx = \int_0^\infty\frac{2\sin x\cos x}{x}dx= \frac{\pi}{2}$$

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