How do I find the mass of a sphere using proportionality? A steel sphere 3.0 cm in diameter has a mass of 0.11 kg. What is the mass of a steel sphere 5.0 cm in diameter?
I know that $m= DV$ where D is density and V is Volume. I am assuming that both spheres have the same density since it is made of steel so I plugged in $1.5$ into $V=\dfrac{4}{3}\pi r^3$ and got $14.14cm^3$. I then plugged $14.14$ into $m= DV$ and got that the density was $0.0078$. Now I can solve for the unknown mass $m=0.0078(\dfrac{4}{3}\pi (2.5)^3)$. I got the mass is $0.51kg$. Did I do this problem correctly? If not could anyone explain what I did wrong?
 A: We are scaling linear dimensions (lengths) by the factor $\frac{5}{3}$.
If we scale linear dimensions by the factor $\lambda$, then volume is scaled by the factor $\lambda^3$. 
So we are scaling volume, and therefore mass, by the factor $\left(\frac{5}{3}\right)^3$.
The new mass is therefore $\left(\frac{5}{3}\right)^3(0.11)$. 
Remark: Your calculation was correct. More work, though!  And suppose that the item was not a ball, but a small statue of a horse, and we were scaling linear dimensions by the factor $\frac{5}{3}$. The scaling argument above would still work, but there is no "volume of a horse" formula.
A: You said you wanted an answer using proportionality. I'll work out the proportion with algebra, only substituting at the end.
m = DV and V = 4πr3/3, so m = 4πDr3/3
Now take the ratio of two masses:
m2/m1 = (4πD2r23/3)/(4πD1r13/3)
Assuming they're the same kind of steel at the same ambient pressure and temperature, density is constant. This means D2 = D1. Now simplify the right side by dividing the top and bottom by 4πD1/3:
m2/m1 = r23/r13
Now solve for m2 by multiplying both sides by m1:
m2 = m1 * r23/r13
Finally, substitute in m1 = 0.11 kg, r1 = 3.0 cm, and r2 = 5.0 cm:
m2 = 0.11 kg * (5.0 cm)3/(3.0 cm)3 = 0.51 kg
