I am wondering if the following relationship in set are true. E stands for is part of the set, C for subset.

$[2]E[1,2,3]$ I would say this is false as the set contains 1,2,3

$[3]E[1,[2],[3]]$ This is true because the set contains $1,[2],[3]$

$1E[1]$ This seems true as the set contains 1

$[1]C[1,2]$ This seems to be true.

$1E[[1],[2]$ This seems false as set contains [1],2

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    $\begingroup$ You are completely correct. Voting to close because no further answer is necessary. Btw, you can use \in and \subset. $\endgroup$ – Rasmus Sep 1 '13 at 16:32
  • $\begingroup$ Thats good to hear..ty $\endgroup$ – Fernando Martinez Sep 1 '13 at 16:33

Yes, indeed, you're "spot on" with each of your answers.

Some formatting/notation tips:

I would suggest using curly braces for denoting sets: E.g. \{ 1, 2, 3\} for $\{1, 2, 3\}$. To denote "is an element of" or "E", use \in: $\in$, and for "is a subset of" ("C"), you can use \subseteq: $\subseteq$, or \subset: $\subset$.

  • $\begingroup$ Needs another TU! =1 $\endgroup$ – Amzoti Sep 2 '13 at 13:48
  • $\begingroup$ thanks for the notation tips $\endgroup$ – Fernando Martinez Sep 4 '13 at 17:28

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