1
$\begingroup$

I am wondering if the following relationship in set are true. E stands for is part of the set, C for subset.

$[2]E[1,2,3]$ I would say this is false as the set contains 1,2,3

$[3]E[1,[2],[3]]$ This is true because the set contains $1,[2],[3]$

$1E[1]$ This seems true as the set contains 1

$[1]C[1,2]$ This seems to be true.

$1E[[1],[2]$ This seems false as set contains [1],2

$\endgroup$
  • 1
    $\begingroup$ You are completely correct. Voting to close because no further answer is necessary. Btw, you can use \in and \subset. $\endgroup$ – Rasmus Sep 1 '13 at 16:32
  • $\begingroup$ Thats good to hear..ty $\endgroup$ – Fernando Martinez Sep 1 '13 at 16:33
2
$\begingroup$

Yes, indeed, you're "spot on" with each of your answers.

Some formatting/notation tips:

I would suggest using curly braces for denoting sets: E.g. \{ 1, 2, 3\} for $\{1, 2, 3\}$. To denote "is an element of" or "E", use \in: $\in$, and for "is a subset of" ("C"), you can use \subseteq: $\subseteq$, or \subset: $\subset$.

$\endgroup$
  • $\begingroup$ Needs another TU! =1 $\endgroup$ – Amzoti Sep 2 '13 at 13:48
  • $\begingroup$ thanks for the notation tips $\endgroup$ – Fernando Martinez Sep 4 '13 at 17:28

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.