# "A secretary had to call all the clients in her company" probably an easy problem that I am really struggling for some reason.

"A secretary had to call all the clients of her company. By the morning she made 1/3 of the calls; in the afternoon she made 3/5 of the calls that were left and at night called the last 64 clients. With how many clients did she talk in the morning?" The answer is 80, but I really don't know how to get to it. I took it from a contest that happens in my country so, I had to translate the problem. One of the things that I tried was x = 1x/3 + 3x/5 + 64, but I got nowhere. This is driving me insane.

Let the total number of calls be $$x$$.
Morning: $$\frac{1}{3}x$$, afternoon: $$\frac{3}{5}(x-\frac{1}{3}x)$$ (because it is the left over ones), night:$$64$$.
So we have $$x=\frac{1}{3}x+\frac{3}{5}(x-\frac{1}{3}x)+64$$. Now solve for $$x$$, which should be $$240$$ and so the morning calls is $$80$$.
In short you got the afternoon one wrong because you were considering $$\frac{3}{5}$$ of the total call, not the left over ones.