I'm working with a two-player normal-form game represented by the following matrix:
I attempted to find the Nash equilibrium in mixed strategies and concluded with the solution to play L with probability 1 and R with probability 0. However, this doesn't align with the observation that R strictly dominates L for player 1.
I'm puzzled by the following:
- If my calculations yield a negative probability, does that mean there is no mixed strategy for either player or only for the player I'm checking on?
- Since the Nash equilibrium found seems to be (R,D), how can my calculation yield playing L with probability 1?
What am I missing in my analysis? Can someone help me understand how to properly find the Nash equilibrium for this game?