I am going through these lecture notes, and I am confused about the proof of Corollary 10.10 there.
Corollary 10.10. Let $A$ be a local noetherian domain with maximal ideal $\mathfrak{p}$, let $g \in A[x]$, and let $B := A[x]/g(x)$. Every maximal ideal $\mathfrak{m}$ of $B$ contains the prime $\mathfrak{p}B$.
In the proof of this, the author writes
The ring $B$ is finitely generated over the noetherian ring $A$, hence a noetherian $A$-module, ...
I don't understand this part, because I think if $g$ is not monic, then $B$ will not be finitely generated? For example, take $A = \mathbb{Z}_{(3)}$, and $g(x) = 3 \in A[x]$. Then $B := A[x]/g(x) = \mathbb{Z}_{(3)}[x]/3\mathbb{Z}_{(3)}[x] = (\mathbb{Z}/3\mathbb{Z})[x]$ which is certainly not finitely generated over $A$? I'm not sure what I am missing here. If there is another source for the proof of this corollary, please let me know. Thank you so much.
deg g > 0
is implied. $\endgroup$