0
$\begingroup$

enter image description here

Does anyone know how I would go about calculating the fixed points of this model?

$\endgroup$

1 Answer 1

2
$\begingroup$

A fixed point of a function $f$ means that $f(x) = x$. In this instance, you want $f(x_{n-1}, y_{n-1}) = (x_n, y_n)$, so if $(x,y)$ is a fixed point, this means that you want $f(x,y) = (x,y)$, i.e.

$x = x + 0.004x + 0.002xy$

$y = y + 0.005y + 0.010xy - 0.001y^2$

So all you have to do is to solve for $x$ and $y$, the most trivial solution being $x = 0$ and $y = 0$, but there are more than one solution.


To find all solutions, we solve the equations:

$0 = 0.004x + 0.002xy = x(0.004 + 0.002y)$

$0 = 0.005y + 0.010xy - 0.001y^2 = y(0.005 + 0.010x - 0.001y)$

For the first equation, there are two solutions, either $x = 0$ or $0.004 + 0.002y = 0$

For the second equation, there are two solutions, either $y = 0$ or $0.005 + 0.010x - 0.001y = 0$.

All you have to do now is to go through all the possibilities of what $x$ and $y$ can be. $x = 0$ and $y = 0$ is the one most easily spotted, try to find the others.

$\endgroup$

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .