0
$\begingroup$

Let $x \bmod 1\in \Bbb R$ be fractional part of $x \in \Bbb R$.

For what pairs of $(x,y) \in \Bbb R^2$ with $x\neq y$ is $x^2 \bmod 1 = (y \bmod 1)^2$? The case of $x=y$ was answered in On an equality of $x \bmod 1$.

What about for higher powers?

$\endgroup$
2
  • 1
    $\begingroup$ This question is kind of wierd. You can always choose $y=\sqrt{\{x^2\}}+a$, where $a$ is an integer. $\endgroup$ Aug 18 '13 at 14:41
  • $\begingroup$ You could write it as an answer $\endgroup$
    – Mr.
    Aug 18 '13 at 14:41

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Browse other questions tagged or ask your own question.