What rules would a person use given b and c to solve a for $1 = \dfrac {2a + 2ab}{c}$.
Specifically the established rule names for ways to solve this.
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$1=\dfrac {a(2+2b)}{c}$ by the distributive property, then $\dfrac {c}{2+2b}=a$ by cancelation with the multiplicative inverse of $\dfrac {2+2b}{c}$. (Note:$c\not=0$ and $b\not = -1$)
