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I computed the answer to be $10 \cdot 9 \cdot 8 \cdot 7$, but apparently we had to do $9 \cdot 9 \cdot 8 \cdot 7$.

But there are $10$ digits between $0$ and $9$, right? Can someone explain to me how this is possible?

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1 Answer 1

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Hint: The first of your four digits can't be $0$ if the number is between $1000$ and $9999$.

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  • $\begingroup$ You're right AWertheim. $\endgroup$ Aug 16, 2013 at 22:15

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