I am having some trouble with the following integral:
$$\int \frac{\ln(15x^5)}{x}$$
I separated the top into:
$$\int \frac{5\ln(x)+ \ln(15)}{x}$$
But, then I don't know where to go from there. I tried $u$ substitution by letting $u=\ln(x)$.
\begin{align} \int 5u &+ \ln (15) \, du \\ \frac{5u^2}{2} &+ \ln(15)u \\ \frac{5(\ln(x))^2}{2}&+\ln(15)\ln(x) \end{align}
Where am I going wrong? Can someone please provide some hints?
Thanks a bunch!