# Inequation with absolute values

How would one proceed in solving this difficult inequation with multiple absolute values? is there a way one should proceed ?

$$\frac{x}{||x|-2|} \le \frac{x-1}{|x-3|}$$

thanks

Discuss several cases: $$x\in(-\infty,-2)\cup(-2 ,0]\; ; \; x\in(0 ,2)\; ;\; x\in(2 ,3)\; ;\; x\in(3 ,+\infty)$$
• @franck The $x-1$ doesn't form its own separate case because it's not absolute valued in the equation. – Ataraxia Aug 14 '13 at 20:24