I have a question regarding the sum of the exterior angles of an n-sided polygon (n-gon). I understand that for a cyclic n-gon, the sum of its exterior angles is always 360 degrees. However, I'm not sure how to prove this for a general n-gon.
I came across a solution that involves drawing n triangles within the n-gon and using the fact that each triangle has an interior angle sum of 180 degrees to find the sum of all the interior angles in the n-gon. To do this, you can start by drawing an n-gon and connecting each vertex to all other vertices to form n triangles. However, I'm having trouble visualizing how to draw the n-gon.
The solution suggests starting with a circle and marking its center point, and then drawing lines from the center to the edges of the circle to form the n-gon. Can anyone provide a more detailed explanation or another approach to solving this problem?
Thank you in advance for your help!