If you were to take this approach, in the context of CS / cryptography education as you mention in your comment, what I think you'd want would be something like:
A cyclic group of order $n$ is a set $A = \{a_0, a_1, a_2, \dots, a_{n-1}\}$ with a binary operator $\star: A^2 \to A$ that satisfies $a_i \star a_j = a_k \iff i + j \equiv k \pmod n$.
Of course, this is hardly an "axiomatic definition" in the sense we're used to from abstract algebra. Rather, it basically just defines a cyclic group as something isomorphic to $(\mathbb Z / n \mathbb Z)^+$, with all the consequences that entails. But for your purposes I think that's enough, and any attempt to get more "axiomatic" than that would just be a pointless exercise in abstraction for its own sake.
Anyway, the obvious problem with this definition is that it effectively defines the group operation in terms of the discrete logarithm — which means that, to compute $x \star y$ based on this definition of $\star$, you must first compute the discrete logarithm of both $x$ and $y$!
Of course that's a perfectly valid way to compute the group operation in situations where it's feasible — for example, if you were trying to do multiplication in the AES field by hand using pencil and paper, by far the quickest way would probably be to use a pregenerated discrete log / antilog table — but it also means that any group representation that allows doing this is useless for any cryptographic algorithms that depend on the hardness of the discrete logarithm problem.
However, if you wanted, you could probably start like this and then introduce the idea that the representation of a cyclic group can be "obfuscated" in such a way that we can still efficiently compute $\star$ while not having an efficient way to compute discrete logarithms.
At that point you could then offer some of the standard examples, like the multiplicative group modulo a prime and/or its subgroups, and show that they can in fact be proven to be cyclic groups even though the discrete logarithm may not be efficiently computable.
Indeed, on some level this is trivial: if you define $a_k \equiv g^k \pmod m$ for some $g$ coprime to $m$, and let $\star$ denote multiplication modulo $m$, then it's not hard to show that $g^n \equiv 1$ for some $n$ and that $\star$ satisfies the definition given above. Of course, determining exactly what the order $n$ is for given $m$ and $g$ can be trickier, but in many specific cases that's not too hard either, especially if you're willing to handwave past some of the deeper number-theoretic lemmas involved in the background.
Would this be any simpler or pedagogically better than the usual approach of starting with a definition of a group and then showing that some groups can be cyclic, even if we may not know how to efficiently compute discrete logs in them? Maybe, maybe not. But I cannot say for sure that it isn't.
One potential advantage of this method is, of course, that it would let you skip the axiomatic definition of a group, which could save a bunch of time and mental effort for students who might never need it again. Then again, being exposed to a bit of abstract algebra might be helpful to prepare the students for later dealing with e.g. finite fields. (Of course it's certainly also possible to give an introduction to finite fields in cryptography without really involving much abstract algebra either.)