# Odds of winning the Malaysian lottery [part 2]

Part 1

Jackpot Bonus number: remaining of number inside the 8 matching number.

Updated: Per ticket is 8 numbers and no need to specify which is bonus number

Grand Prize: 8 matching number from 36 numbers Probability: 1 in (36 choose 8)

2nd prize: 7 matching number from 36 numbers + (any 1 of 2 bonus numbers)

3rd prize: 7 matching numbers from 36 numbers Probability: 1 in (36 choose 7)

4h prize: 6 matching number from 36 numbers + (any 1 of 2 bonus numbers)

What is the probability of winning 2nd prize and 4th prize respectively?

• I guess a lottery ticket just asks to choose any 10 numbers from 36 possible. Am I correct? This is the first time I hear about bonus numbers and they confuse me a bit. Commented Feb 25, 2023 at 16:01
• I now think that my assumption is not correct and only 8 numbers should be chosen. Commented Feb 25, 2023 at 18:30
• Your answer for question 3 is wrong ; you already had explanations for very similar question in the other topic. Commented Feb 25, 2023 at 19:47
• @kludg Per ticket is pick 8 numbers and no need to specify which is bonus number Commented Feb 25, 2023 at 19:52
• Hi! To avoid down-votes and close-votes, please provide us some context for this question, such as: (a) Is this homework? (b) If so, what course are you taking? (c) What specific topic are you covering at the moment? (d) What do you know that you think might be connected? (e) If you're stuck, what are you stuck on? For example, do you know what to apply, but don't know how to apply it, or do you not know what to apply? Please put these facts in your original post, not as responses to this comment, as comments may be deleted without warning. Commented Feb 25, 2023 at 21:02

Divide number into $$8$$ winning, $$2$$ bonus, $$26$$ useless

Win $$2nd$$ prize = $$\Large{\binom87\binom21\binom{26}0\over\binom{36}8}\approx1\; in\; 1,891, 271$$

You should be able to work out $$4th$$ prize similarly as

$$\Large{\binom86\binom21\binom{26}1\over\binom{36}8}$$

• The condition is they are 10 draws out of 36. The 2 bonus numbers will come from the same 36 numbers, thus they will not be repetitive of numbers Commented Feb 25, 2023 at 14:10
• @maths123: But will your ticket have $8$ numbers or $10$ numbers ? Commented Feb 25, 2023 at 14:15
• 10 number version added Commented Feb 25, 2023 at 17:23
• I think this version includes the first prize. That is why I used 25 possible values for the "free" numbers in the 2nd prize calculation. Commented Feb 25, 2023 at 17:39
• @kludg: I don't understand, $8$ are prime, $2$ are subprime and the remaining $26$ are of no use. As I see it, there is a clear trifurcation. Commented Feb 25, 2023 at 18:27