While studying smooth manifolds and differential forms I have come across multiple definitions of the wedge product, and I have been having some trouble seeing the equivalence between them.
At the most general level, if we have two alternating tensors $f$ and $g$, of size $k$ and $\ell$ respectively, then $f \wedge g$ is another alternating tensor of size $(k + \ell)$. This suggests the wedge product is a sort of "multiplication operator" amongst tensors. If we apply this definition to two differential forms $\omega$ and $\tau$, then $\omega \wedge \tau$ makes sense because at each point $p$ in a manifold $M$, $\omega_p$ and $\tau_p$ are just alternating tensors so $\omega_p \wedge \tau_p = (\omega \wedge \tau)_p$ is an example of the above definition.
My first question: is there any interpretation of $\omega \wedge \tau$ that is not pointwise?
On the other hand, I have read that the wedge product of $n$ vectors is the same as the determinant of the $n$ vectors, or equivalently, the volume of the parallelepiped which they span. Using $\mathbb{R}^3$ as an example, we use linearity to obtain something of the form $$c_1 (e_1 \wedge e_2) + c_2(e_1\wedge e_3) + c_3 (e_2 \wedge e_3)$$ for some constants $c_i$.
My second question: in the above example the basis vectors $e_i$ are not alternating multilinear functions, so how does the wedge product make sense here? How are we to interpret it in view of the definition I gave?
My third question: my current interpretation of differential forms comes straight from their definition, so they are a function that assigns to each point in the manifold an alternating tensor. Does there exist a geometric interpretation of the wedge product of differential forms (or even just differential forms themselves for that matter) similar to the wedge product of vectors?