Quadratic forms, bilinear forms and norms I’m studying linear algebra, and i saw the following statement: “As we associated a norm to an inner product, we can associate a quadratic form to a bilinear form, and the quadratic form behaves like the square of a norm of a vector.”
Context: this statement is made after talking about bilinear forms and before defining the associated quadratic form.
There are two proposition that I think “support” this statement:

*

*Let $\varphi$ be a bilinear form and $\phi$ be the associated quadratic form. Let $u$, $v$ be vectors and $t \in \mathbb{R}$. Then we can define the polarization identities, in a similar way we do for the norm and for the inner product:
\begin{gather*}
  4\varphi (u, v) = \phi (u + v) - \phi (u - v) \,,\\
  2\varphi (u, v) = \phi (u + v) - \phi (u) - \phi(v) \,.
\end{gather*}


*Let $\phi$ be an associated quadratic form. Then $\phi(0) = 0$ and $\phi(tv)=t^2\phi(v)$.
Still, I don’t understand the use of saying that a quadratic form is similar to a norm: I’d expect that this would be useful if, as the norm associated to a inner product lets us measure lengths and angles, the quadratic form is a kind of generalization of measure of lengths and angles (since bilinear forms are a generalization of inner products). But I can’t find anything that supports this, and I can’t really have any intuition of what a quadratic form is, except from the fact that you can graph it as with any other function (for example, real quadratic forms represent quadrics).
 A: If you have a matrix $A=BB^\top$, then the quadratic form $$x^\top Ax=x^\top BB^\top x=y^\top y=\|y\|_2^2 $$ measures the length of the vector  $y=B^\top x$ and squares it. So what you are doing is projecting the vector $x$ into the column-space of $B$ and taking the norm in that new space.
Geometrical Interpretation
You can show that the contour lines of the function $x^\top Ax$ define ellipses (as long as $A$ is positive semidefinite), so in that sense the matrix $A$ transform the vectors in the space (it transforms the space). If $A=I$, i.e. identity matrix, the level curves are circular, there is a notion of "isotropic" meaning that to compute the length of a vector, you can simply "take a ruler" and measure the vector straight. If there is a matrix, that is no more the case.
To be an ellipse the matrix of the quadratic form has to be positive semidefinite. Otherwise it can still have a geometric illustration, for instance the hyperbola.
This might be of great help: https://en.wikipedia.org/wiki/Matrix_representation_of_conic_sections#Standard_form_of_a_central_conic
