I have a base-10 exponential function with the equation:

$$y = 0.000346 \cdot 10^{0.00676x} + 0.148$$

I am trying to linearize this equation but unable to do so. I tried taking $\log(y)$ in the $y$-axis and $\log(x)$ in the $x$-axis but I am never getting a straight line. In fact, taking $\log(y)$ gives me negative $y$-values. Any help would be appreciated.

I have attached an imgur link to my graph below since I am unable to embed it here. Thank you so much.

imgur link to graph

  • 2
    $\begingroup$ Hint: move the constant term first, then take logarithms on both sides. $\endgroup$ Dec 29, 2022 at 6:58

1 Answer 1


$$y=A\cdot 10^{Bx}+C$$

$$y-C=A\cdot 10^{Bx}$$

if $A>0$, then $y-C$ should be positive, hence we can take logarithm

$$\log_{10}(y-C)=\log A + Bx $$

Now can you see what should $Y$ be for the linearized model?


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