Find x in Z from this inequality:
$$\frac32\left|x-\frac32\right|=\frac53|2x|-\frac16$$
I tried to solve it,but i don't know how to continue:
$$\frac32\left|2x-\frac32\right|=\frac103|x|-\frac16$$ $$\frac34|2x-3|=\frac{20|x|-1}6$$ $$9|2x-3|=40|x|-2$$
Here i stoped because i don't know what's the next step.