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According to the textbook my lecturer is following, a set of data is "said to be symmetric about the value x0 if the frequencies of the values x0 − c and x0 + c are the same for all c. That is, for every constant c, there are just as many data points that are c less than x0 as there are that are c greater than x0"

So, according to the book, when we have

 values = [0,2,3,4,6,0] 

and

 frequencies = [1,2,3,2,1,0]

the data set is symmetric around 3. (Put aside how the value '0' can have a frequency of 1 and 0 at the same time. I'm lost there).

My lecturer has now issued a quiz asking whether the following data sets are symmetric, approximately symmetric or not at all symmetric:

 Data set A: 5, 9, 5, 4, 0, 4, 5

 Data set B: 5, 2, 5, 4, 2, 3, 1, 5, 0, 2, 1, 4

 Data set C: 2, 8, 3, 5, 6, 0

 Data set D: 1, 0, 1, 3, 1, 3, 4, 2

But here, there is just one data set each time and never a set of values with an associated set of frequencies, so surely the definitions don't apply? I am being stupid, clearly, but quite confused about what is being asked of me. Can anyone help?

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  • $\begingroup$ Perhaps each observation was seen once, so in data set A you had $5$ appearing three times, $4$ appearing two times and $0$ and $9$ once each $\endgroup$
    – Henry
    Oct 17, 2022 at 22:21

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