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My task is to count number of different paths from A to B, moving only down or right so that path does not pass through walls on picture below.

picture

So, in both of these walls we have $4$ segments. For the top right one I tried to find all paths that pass through segment $i(i=1,2,3,4)$.

Let $A_i$ be number of paths that pass through segment $i$ for the top wall.

Now, I've found cardinality of those $4$ sets, and got following results: $|A_1|$ = $5 \choose 4$ $9 \choose 4$ $|A_2|$ = $7 \choose 4$ $8 \choose 3$ $|A_3|$ = $8 \choose 5$ $7 \choose 3$ $|A_4|$ = $9\choose 5$ $5 \choose 4$

For the next part, using inclusion exclusion formula, I should find intersection of all combinations of $2,3$ and $4$ sets, but not sure how to do that. For the cardinalities above I first found path from A to starting point of segment, and then from end point of segment to B(without that segment). Any idea how to continue?

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    $\begingroup$ Again, what does "shortest" mean? Unless I misunderstand the rules, all the paths from $A$ to $B$ have the same length. $\endgroup$
    – lulu
    Commented Oct 3, 2022 at 11:29
  • $\begingroup$ Are the paths from square to square rather than on the grid lines? $\endgroup$ Commented Oct 3, 2022 at 11:30
  • $\begingroup$ Well it is said that we can move from cell to cell, so I guess from square to square. $\endgroup$
    – marc
    Commented Oct 3, 2022 at 11:31

2 Answers 2

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Don't use inclusion–exclusion at top-level for this one. Instead observe that the path must follow exactly of three routes,

  • Through the $(1,5)$ and $(4,8)$ squares in the southwest. The path from $(1,1)$ to $(1,5)$ and $(4,8)$ to $(8,8)$ are unique; there are $\binom63-1=19$ paths from $(1,5)$ to $(4,8)$, the $-1$ because of the wall protrusion blocking the $(5,4)$ square. Thus there are $19$ paths on this route.
  • Through the $(5,1)$ and $(8,4)$ squares in the northeast – also $19$ paths by symmetry.
  • Through the $(4,4)$ and $(5,5)$ squares. The number of possibilities for each segment is an unconstrained lattice-paths-in-rectangle problem, so they can be multiplied: $\binom63\binom21\binom63=800$.

Thus there are $800+19+19=838$ admissible paths in all.

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  • $\begingroup$ Thanks a lot! Can you just explain me once more why are we substracting 1 in first and second case? And why we don't do that in third case? $\endgroup$
    – marc
    Commented Oct 3, 2022 at 11:46
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    $\begingroup$ @marc $1$ is the number of paths from $(5,1)$ to $(8,4)$ passing through the inaccessible square $(5,4)$. $\endgroup$ Commented Oct 3, 2022 at 11:48
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Using full inclusion-exclusion for all the segments of the wall seems like a fairly inefficient way to get the result here. As a hint: use the fact that all such paths either go through $(5,1)$ and $(8,4)$, or through $(4,4)$ and $(5,5)$, or through $(1,5)$ and $(4,8)$, and that these possibilities are mutually exclusive. For each possibility the number of paths seems easy to determine.

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