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let us consider following problem:

we have inscribed triangle,like this

enter image description here

we are asked to determine if given $x$ is acute or obtuse,$O$ is center of circle,as i know if $CB$ would be diameter,then $x$ would be $90$,or $CAB$ would be right triangle,but in this case what it should be?if i trust diagram then maybe it seems that it is more then $90$,but because GRE said that dont trust diagram,then what i should know about it?

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  • $\begingroup$ @labbhattacharjee but how do you show that $CAB$ is greater than $DAE$? It seems like you are resorting to the diagram again. $\endgroup$ – BlackAdder Jul 28 '13 at 14:29
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There is a proposition that says that if you connect $C$ to $O$ and $B$ to $O$, then the reflex $\angle BOC$ is twice of $\angle BAC$. And since reflex $\angle BOC >180^{\circ}$, we are done.

To argue that the reflex $\angle BOC >180^{\circ}$, we can just say that the usual $\angle BOC <180^{\circ}$, because it is contained in the triangle $BOC$.

See: http://www.mathopenref.com/arccentralangletheorem.html (The prop will be a corollary of that.)

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  • $\begingroup$ sorry $BOC$ is more then $180$? $\endgroup$ – dato datuashvili Jul 28 '13 at 14:39
  • $\begingroup$ @dato Yes! Read carefully I said the REFLEX. :) $\endgroup$ – BlackAdder Jul 28 '13 at 14:40
  • $\begingroup$ i still did not understand sorry $\endgroup$ – dato datuashvili Jul 28 '13 at 14:41
  • $\begingroup$ There are two angles when two lines meet at a point. Usually, what we call the "angle" is the inside angle, ie angle which is less than $180$. The reflex angle is the one which is greater than $180$. $\endgroup$ – BlackAdder Jul 28 '13 at 14:43
  • $\begingroup$ you mean angle which is not in $BOC$ triangle? $\endgroup$ – dato datuashvili Jul 28 '13 at 14:45

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