$ f(x) \begin{cases} \frac{3x-6}{x^4-4}, 0 < x < 2 \\ 0, x=2 \\ \frac{x-2}{\sqrt{3-x} -1} 2 < x < 3 \end{cases}$
For this expression, can I say that these 3 cases, the limit does not exist because when $x=2$ or as $x$ approaches $2$ from left and right , all of the 3 functions have different values (when I substitute $x=2$) thus the limit does not have a finite and unique value. Is that right to say that? If not, when does a limit not exist?
$\lim_{x \to 2^+}$
$\lim_{x \to 2^-}$
$\lim_{x \to 2}$