3
$\begingroup$

The arclength of a circle is just:

$$r\theta$$

is there relation like this for a hyperbola? for example:

$$r\phi$$

where phi is the argument of the hyperbolic functions.

$\endgroup$

1 Answer 1

5
$\begingroup$

Using the parametrization $$x=a \cosh(\theta) \qquad \text{and} \qquad y=b\sinh(\theta)$$ you need to compute $$\int \sqrt{a^2 \sinh ^2(\theta )+b^2 \cosh ^2(\theta )}\,d\theta=-i b E\left(i \theta \left|\frac{a^2}{b^2}+1\right.\right)$$ where appears (just as for the ellipse) the elliptic integral of the second kind.

Now, use bounds.

$\endgroup$

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .