The universal property definition of a limit (of a projective system, in this case) tells you what property an object (+ morphisms) must have to be that limit. It is a definition that works for every category.
Now, some categories 'have projective limits' and some don't and to show that a particular category 'has projective limits', you need to actually construct that object.
Now $$\text{Hom}_{\textbf{Sets}^{\mathcal{I}^{\text{op}}}}(Pt, P)$$ is a construction of the projective limit in the category of sets.
Here $Pt \colon {\cal I}^{\text{op}} \to \textbf{Sets}$ is the constant functor that always gives the one-point set. An element of $\text{Hom}_{\textbf{Sets}^{\mathcal{I}^{\text{op}}}}(Pt, P)$ consists of a family of morphisms $f_i \colon Pt(i) \to P(i)$, for $i \in {\mathcal I}$, that commute with the morphisms $P(i \to j) \colon P(j) \to P(i)$ and $Pt(i \to j) \colon Pt(j) \to Pt(i)$. Since $Pt(i)$ is just a one-point set, you can as well see that as elements $f_i \in P(i)$, for $i \in {\mathcal I}$, such that for every morphism $k \colon i \to j$ in ${\cal I}$, $P(k)(f_j) = f_i$. This looks more like the 'usual' construction of the projective limit in $\textbf{Sets}$ as a family of ${\cal I}$-indexed elements of $P(i)$ that map to each other under the morphisms $P(i \to j)$.
Of course, it needs a proof that this is indeed the projective limit in $\textbf{Sets}$.