Locate and classify the singularity of $\frac{e^{z-1}-1}{z^4-1}$

Question

Locate and classify the singularity of $\frac{e^{z-1}-1}{z^4-1}$.

I may be a bit confused with the idea of the classification of the singularities, but if I have that:

$\frac{e^{z-1}-1}{z^4-1}=\frac{e^{z-1}-1}{(z+1)(z-1)(z+i)(z-i)}$ I am not allowed to say that the poles $\pm 1, \pm i$ are simple because I did not expand the numerator yet. Correct?

I know that $e^{z-1}-1 = \sum_{n \geq 0} \frac{(z-1)^n}{n!}-1 =(z-1) \sum_{n \geq 2}\frac{(z-1)^n}{n!}$. Now I see that:

$\frac{e^{z-1}-1}{z^4-1} = \frac{(z-1) \sum_{n \geq 2}\frac{(z-1)^n}{n!}}{(z+1)(z-1)(z+i)(z-i)} = \frac{\sum_{n \geq 2}\frac{(z-1)^n}{n!}}{(z+1)(z+i)(z-i)}$.

Now, I can conclude that $-1, \pm i$ are simple poles and $1$ is actually a removable singularity. Is that correct? Is there a "general procedure" to start with such tasks?

Correction: There is a mistake in the expansion. See the comment below.

Answer 1

Just note that $$\lim_{z\to 1}(z-1)\frac{e^{z-1}-1}{z^4-1}=0$$ so its removable. For the others just note that $-1,i,-i$ are simple zeros of $z^4-1$, and since there are no problems in that points in the numerator, they are simple poles of the function

Answer 2

Your general methodology is correct (other than the small miscalculation mentioned in my comment).

In general, to classify singularities of a function:

1. Look for any essential singularities. In general, these will either be branch points, such as if you calculate $\ln(z-a)$ or points where you do something like $e^{(\frac1{z-a})}$

2. Write the function in the form $\frac{f(z)}{g(z)}$, where $f(z)$ and $g(z)$ are continuous everywhere (except at the essential singularities that you found)

3. Find the roots of $g(z)$, $r_i$, and note their multipliicties $m_i$.

4. Find the zeroes of $f(z)$, $p_j$, and note their multiplicities $n_j$.

5. If $r_i\not\in\{p_j\}$, then it is a pole of order $m_i$, If $r_i=p_j$, then if $m_i>n_j$, it is a pole of order $m_i-n_j$, and if $m_i\leq n_j$, it is a removable singularity