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Find the complement of $xy(y+y'z) + x'z$

I solve this problem but get 3 different solution by using 3 different methods (rules of boolean algebra)

Solution that I get each time

  1. $\quad x'z'+xy'+y'z'$
  2. $\quad xy+xyz'$
  3. $\quad y'z'$
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  • $\begingroup$ xy(y + y'z) + x'z = xyy + xyy'z + x'z = xy + x'z. $\endgroup$
    – Mike Smith
    Jun 23 at 5:07
  • $\begingroup$ @MikeSmith please read the question again (find complement) $\endgroup$
    – Digit.
    Jun 23 at 5:08
  • $\begingroup$ Please answer this question $\endgroup$
    – Digit.
    Jun 23 at 5:52
  • 2
    $\begingroup$ What is 2 in BA? $\endgroup$ Jun 23 at 7:42
  • $\begingroup$ @MauroALLEGRANZA I can't understand please explain $\endgroup$
    – Digit.
    Jun 23 at 8:58

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