This question already has an answer here:

If there are none why not?

Thanks in advance.


marked as duplicate by Steven Stadnicki, Pedro Tamaroff, Amzoti, Start wearing purple, Clayton Jul 19 '13 at 22:39

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  • 2
    $\begingroup$ Nigh-trivially, if there were then the square root of two would be rational ($a^2+a^2=c^2$, so $2a^2=c^2$, so $2=\frac{c^2}{a^2}$). $\endgroup$ – Steven Stadnicki Jul 19 '13 at 21:58

Note that this can be written as $$2=\left(\frac{c}a\right)^2$$

Is $\sqrt 2$ rational?


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