This question already has an answer here:
If there are none why not?
Thanks in advance.
1
$\begingroup$
$\endgroup$
marked as duplicate by Steven Stadnicki, Pedro Tamaroff♦, Amzoti, Start wearing purple, Clayton Jul 19 '13 at 22:39
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
-
2$\begingroup$ Nigh-trivially, if there were then the square root of two would be rational ($a^2+a^2=c^2$, so $2a^2=c^2$, so $2=\frac{c^2}{a^2}$). $\endgroup$ – Steven Stadnicki Jul 19 '13 at 21:58
6
$\begingroup$
$\endgroup$
Note that this can be written as $$2=\left(\frac{c}a\right)^2$$
Is $\sqrt 2$ rational?
