What is the probability that Camilla and Cameron are paired with each other? Textbook problem: A teacher with a math class of 20 students randomly pairs the students to take a test. What is the probability that Camilla and Cameron, two students in the class, are paired with each other?
My answer: 1/190.  There is only one such pair out of the 20-choose-2 possible pairings.
Their answer: 1/19.  Camilla can be paired with 19 students and only one such pairing is with Cameron.
Question: What principle am I missing in my reasoning that would help me to see why their answer is right and mine wrong?  It's like I follow their line of reasoning too but don't see what underlying assumption differentiates the answers to see how I can frame the problem correctly on my own.
Textbook: Chapter 26 from The Art of Problem Solving (Volume I) by Rusczyk and Lehoczky.
 A: You're missing that the teacher will pair up all the students, making 10 pairs.  Camilla and Cameron could be any of these 10.
A: The 190 comes from counting all the possible pairs of students, including those that are not Cameron or Camilla.  You need to zero in on only Cameron or Camilla pairs.  Camilla will be paired with someone, and that is a certainty.  She cannot be paired with herself, so that leaves only 19 other students she can be paired with.
If instead of pairing up everyone, you only picked two students at random to make one pair out of the 20, then the odds would be 1/190.
A: $\mathbf{\text{For another approach:}}$
Let assume that the boxes represent  groups such that two adjacent boxes are in the same group. $$\fbox{+}\fbox{+} \quad\fbox{+}\fbox{+} \quad\fbox{+}\fbox{+} \quad\fbox{+}\fbox{+} \quad\fbox{+}\fbox{+} \quad\fbox{+}\fbox{+} \quad\fbox{+}\fbox{+} \quad\fbox{+}\fbox{+} \quad\fbox{+}\fbox{+} \quad\fbox{+}\fbox{+} \quad$$
Now , let Camilla select one of the position , she can do it $\frac{20}{20}=1$ ways.After that Cameron must select an empty space , but we want that they are in the same group , so if we assume that Camilla selected the position $\color{red}{1}$ , then Cameran must select position $2$ among $19$ possible empty position. As you see , the probability that Cameron select the position $2$ is $1/19$ , then the the probability that they are in same group is $1/19$ $$\fbox{+}\fbox{+} \quad\fbox{+}\fbox{+} \quad\fbox{+}\fbox{+} \quad\fbox{+}\fbox{+} \quad\fbox{+}\fbox{+} \quad\fbox{$\color{red}{1}$}\fbox{2} \quad\fbox{+}\fbox{+} \quad\fbox{+}\fbox{+} \quad\fbox{+}\fbox{+} \quad\fbox{+}\fbox{+} \quad$$
