Theorem 7.11: Suppose $f_n \to f$ uniformly on a set $E$ in a metric space. Let $x$ be a limit point of $E$, and suppose that $$\lim_{t\to x} f_n(t) = A_n \qquad (n \in N).$$ Then $\{A_n\}$ converges, and $$\lim_{t\to x} f(t) = \lim_{n\to \infty} A_n.$$ In other words, the conclusion is that
$$\lim_{n\to\infty}\lim_{t\to x}f_n(t)=\lim_{t\to x}\lim_{n\to \infty}f_n(t)$$
Theorem 7.12: If $(f_n)$ is a sequence of continuous functions on $E$ and if $f_n \to f$ uniformly, then $f$ is continuous on $E$.
I guess I'm having an issue understanding what theorem 7.11 is actually saying in English? Does the conclusion mean that the limit function of $(f_n)$ is continuous at any limit point of $E$? Why is it that continuity for a limit function looks like $$\lim_{n\to\infty}\lim_{t\to x}f_n(t)=\lim_{t\to x}\lim_{n\to \infty}f_n(t)$$ and not something more like $$ \lim_{t \rightarrow x} f(t) = f(x). $$ Why does it follow naturally from 7.11 that 7.12 holds? I feel like I'm missing a simple understanding of what theorem 7.11 is actually saying, although I feel like I understand the proof (which is probably wrong to say because I don't understand the conclusion). Any insights are greatly appreciated.