'Non-algebraic Calabi-Yau' threefolds By a Calabi-Yau threefold I mean a simply connected compact Kahler threefold with trivial canonical bundle.
By an algebraic compact complex manifold, I mean one that admits a closed immersion into a complex projective space.
What are examples of non-algebraic Calabi-Yau threefolds? Or is there none?
What I know: if the Calabi-Yau threefold $ M $ has $ h^{2,0} (M) = 0 $, then it is algebraic. (Algebraicity holds for any compact Kahler manifold with the vanishing condition, btw). So any such example must have nonzero $ h^{2,0} $.
I don't know the Ricci flow viewpoint to this subject, so I'm probably missing something but I'm eager to learn.
 A: All Calabi-Yau threefolds as you defined them are algebraic. In fact any  Calabi-Yau manifold of complex dimension $\geq 3$ is algebraic. An important property here is that your manifold is simply connected. Otherwise there are many examples like complex tori which are not algebraic. The only proof that I am aware of is due to D. Joyce and is published in [this paper][1] and also in
Gross, Mark (ed.); Huybrechts, Daniel (ed.); Joyce, Dominic (ed.), Calabi-Yau manifolds and related geometries. Lectures at a summer school in Nordfjordeid, Norway, June 2001, Universitext. Berlin: Springer. viii, 239 p. EUR 49.95/net; sFr. 86.00; \textsterling 35.00; $ 59.95 (2003). ZBL1001.00028.
[1]: https://arxiv.org/abs/math/0108088
A: This seems very simple, but I believe it is correct. Upon revisiting it again, it should never have been so complicated.
If $ X $ is a CY3 as defined in the question, $ X $ is simply connected so $ H^1(X, \mathbb{C} ) = 0 $ after abelianization of $ \pi_1 $ and Poincare duality. Next since $ X $ is Kahler, $ H^1(X, \mathcal{O}_X) = 0 $ and finally using Serre duality alongwith the fact that $ \omega_X $ is trivial implies $ H^2(X, \mathcal{O}_X ) = 0 $. Then the general fact stated in the original question implies that $ X $ is projective.
