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How can I integrate $$\int\frac{\log|x|}{x\sqrt{1+\log|x|}}\,dx\;\;?$$

I'm not sure what I should put equal to $\,u.$

Can someone give me a hint on how to solve this question? I don't need a full solution, I want to try it on my own.

Thanks!

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    $\begingroup$ Substitute $u = \log \lvert x\rvert$. Be careful with the sign of $x$. $\endgroup$ – Daniel Fischer Jul 5 '13 at 18:52
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Hint: Let $u = \log|x|$. Then $\;du = \dfrac {1}{x}\,dx$.

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  • $\begingroup$ @amWhy: Looks spot on to me ;-) +1 $\endgroup$ – Amzoti Jul 5 '13 at 19:54

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