You have two six-sided dice. What is the probability that the larger number rolled will be at LEAST 5?
I have listed out all the possible rolls. You can set dice 2 equal to 5, and roll dice one. The possible rolls are (1,5), (2,5), (3,5), (4,5). Do the same thing, but this time dice 2 is set to 6. We have (1,6), (2,6), (3,6), (4,6), and (5,6). These 9 possible rolls can happen with setting the 1st dice to both 5 and 6 as well. Giving us a total of 18 possible rolls $$\therefore P=18/36$$
However, the answer I'm given states that $P=20/36$. I'm having trouble understanding why.