In the triangle $ABC$ $M$ is the middle of the side $AB$ and $CE$ is an altitude. Find the angles of triangle $ABC$ if $CM$ and $CE$ split the angle $ACB$ in three equal parts.
I've figured out that triangles $CME$ and $CBE$ are congruent, but I'm not sure what to do exactly to be able to find out the exact angles of triangle $ABC$. ($ACB=3x,ABC=90-x,CAB=270-2x$).
Any help is appreciated, thanks!