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I just recently start to learn cos. I found out when I use different calculators to calculate cos, sometimes may get different results which is quite confusing.

For example, cos(35), I am calculating degrees.

on 1 calculator:enter image description here

on another calcuator: enter image description here

Could anyone explain me why this happens and which one is correct?

It is very confusing for me.

Thanks for any responds.

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    $\begingroup$ Did you mean $35$ degrees or $35$ radians? $\endgroup$
    – lulu
    Commented Jan 11, 2022 at 15:58
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    $\begingroup$ @lulu I think as you $\endgroup$
    – Mikasa
    Commented Jan 11, 2022 at 15:59
  • $\begingroup$ @lulu, I am calculating degrees $\endgroup$
    – Sahil
    Commented Jan 11, 2022 at 16:00
  • $\begingroup$ Do your calculators know that? $35$ radians is $2005$ degrees. $\endgroup$
    – lulu
    Commented Jan 11, 2022 at 16:01
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    $\begingroup$ You may be trying to calculate degrees but the second calculator is calculator is calculator radians. $\cos 35^0 = 0.8195204$ but $\cos 35\ radians = -0.90369255$. That's what's happening. $\endgroup$
    – fleablood
    Commented Jan 11, 2022 at 16:05

2 Answers 2

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On the first calculator the calculator is calibrated to take input in degrees whereas in second it is in radians .

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The first calculator is doing degrees. $\cos 35^\circ \approx 0.819$. This is reasonable because $0< 35 < 90$ so the $\sin/\cos$ values will both be positive. $30 < 35 < 45$ so $\cos 30^\circ =\frac {\sqrt 3}2 > \cos 35^\circ > \cos 45^\circ =\frac 1{\sqrt 2}$ so the value $0.819...$ is reasonable. $-0.9036...$ is not.

The second calculator is doing radians and for radian input $35$ is a strange input but not impossible. $35 = \frac {35}{\pi} \pi \approx 11.14 \pi$. As trig values repeat every $2\pi$ turns, $\cos 35 = \cos 11.14 \pi = \cos 1.14\pi$. As $\cos \pi = -1$, we have $\cos 1.14$ will be "kind of" close to $-1$. And $-0.9036...$ is reasonable for radians.

Alternatively. $360^\circ = 2\pi \ radians$ so $1\ radian = \frac {360}{2\pi}^\circ$ and $35\ radians = 35\times \frac {360}{2\pi}^\circ \approx 2005.35^\circ$. As trig values repeat every $360^\circ$, we know $\cos 2005.35^\circ = \cos (5\cdot 360 + 205.35)^\circ = \cos 205.35^\circ = \cos (180^\circ + 25.35^\circ)$. As $\cos 180 = -1$ then $\cos 205.35$ should be "kind of" close to $-1$ and that's a reasonable answer for $\cos 2005.35^\circ$.

(More guestimation: $\cos (180 + k)^\circ = - \cos k^\circ$ so $\cos 205^\circ = \cos (180 + 25)^\circ = -\cos 25^\circ$. As $0 < 25 < 30$ we have $1=\cos 0 > \cos 25 > \cos 30 = \frac {\sqrt 3}2 \approx 0.866$ so $\cos 25^\circ \approx 0.9036...$ is a reasonable answer and $-0.9306...$ is a reasonable answer for $\cos 2005^\circ$.)

tl;dr: Doing trig with degrees (1 circle = $360^\circ$) and doing trig with radians (1 circle = $2\pi$ radians) will have very different results. One calculator is using degrees. The other is using radians.... That's my final answer.

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  • $\begingroup$ Thanks so much for the detailed answer! $\endgroup$
    – Sahil
    Commented Jan 11, 2022 at 21:08

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