In section 4 page 12 of the article Cohomologie équivariante et théorème de Stokes, there is a statement which says that

if we consider the action of the $S^1$ (parametrized by the angle $\phi$) on itself is by rotations. Then this action is generated by the vector field $\frac{\partial}{\partial \phi}$.

what does it mean in for a group action to be generated by a vector field ?


1 Answer 1


In general, a vector field gives us an action by $\Bbb R$ by letting the result of $t\in\Bbb R$ acting on the point $x\in X$ be "follow the flow of the vector field for $t$ seconds, starting at $x$". In the concrete example, $2\pi$ "seconds" of flow tkae every point back to the origin, thus allowing us to view the action by $\Bbb R$ as an action by $\Bbb R/2\pi\Bbb Z\cong S^1$.

  • $\begingroup$ Thank you very much @Hagen von Eitzen. $\endgroup$
    – Mira
    Commented Jan 5, 2022 at 16:18

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