I am trying to solve a problem that at some point gives me this:

$$ f=C\cdot g^{+} $$

I am confused at to what that $+$ means. Does it indicate that g must be positive? Because that's the only time my calculations work.


1 Answer 1


It's probably $$x^+=\begin{cases}x&\text{if }x\ge0\\ 0&\text{if }x<0\end{cases}$$

See positive and negative part.

  • 1
    $\begingroup$ And for functions $f$ the notation is overloaded to $f^{+}$ to denote the positive part of $f$ taken pointwise. Concretely: $$f^{+}(x) = \begin{cases} f(x) & \text{if $f(x) \geq 0$} \\ 0 & \text{if $f(x) < 0$}\end{cases}$$ $\endgroup$
    – ComFreek
    Nov 21, 2021 at 20:39

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