Is there an efficient way to add minutes in your head? Every week I hop on a treadmill and figure out how long I need to run.  I am given the pace:
Pace = 7:41/mile = (7 minutes + 41 seconds) per mile
I need to add this up to calculate how long I should run to run 1.5 miles.  I use the formula
7:41 + (7:41/2) = ? 1.5 mile
I find this somewhat difficult to calculate in my head, especially while I am starting my warmup.  Converting to seconds doesn't make it any easier.  Do you have any suggestions as to how I can do this more efficiently?
 A: I recommend splitting it up in your head. 7:41 is 7 minutes and 41 seconds. We know that half of 7 minutes is 3 minutes and a half. Half of 41 is about 20. So we add these to get 3:50 or so, and add that to 7:41. Even when I add them, I take 10 seconds from 7:41 (getting 7:31) and add it to 3:50 (getting 4:00) so that 11:31 is that much easier.
That's how I process it mentally, anyway.
Alternately, I estimate a little. I know that 8 minutes is 480 seconds, and that 7:41 is therefore about 5% less than 480 (I think that 20 seconds less than a minute is about half of the 48 seconds that is 10% of 480 - obviously, we could be more precise, but I'm just giving an example of estimation). So if I want to go a mile and a half, I want to go about 5% less than 12 minutes. As 12 minutes is 720 seconds, 10% of 720 is 72, so 5% is 36. So I would approximate the amount of time I have to run as about 12:00 - 0:36 = 11:24.
Both yield things that are close enough, but if I were worried, I would just run for an additional 20 seconds or so to make up any shortcomings. Is that what you were looking for?
NOTE: thanks to amWhy for pointing out my incapability of multiplying 6 by 8.
A: I understand your question as this:  "How do I efficiently divide numbers by $2$ in sexagismal. (Base 60)"
Suppose you have $a*60+b$ as your time.  In your case, $a=7$, $b=41$.  To divide by two, just do it the way you normally would, but carrying is by $60$ instead of $10$.  (Base $60$ instead of base $10$)
Divide $a$ by two.  If it is even, no problem.  If it is odd, then you "carry" a 60 over to $b$.  So when dividing $7:41$, we get $3: \frac{41+60}{2}$.  Then you just divide $b$ by $2$ (or $b+60$ if we had to carry).
So to divide $7:41$ by two, we get $3:50.5$.  Lets try another.  How about $16:56$?  Well the first term is even so we just get $8:28$.  What about $27:32$?  Well, the first part will be $13$, we add $60$ to $32$ to get $92$, then divide this by two, so the answer is $13:46$.  
You try one:  What is $9:51$ divided by two? (answer at end)
I hope this was helpful,
Important Note: Notice that this works for other numbers besides just dividing by $2$.  Dividing by any number in base $60$ is the same, we just carry $60$'s instead of $10$'s.
Even more generally, notice this works for any base $b$.  Division base $b$ is just done by carrying $b$ instead of $10$.
Answer:  $9:51$ divided by two is $4:55.5$.  We divide $9$ by two, and get $4$, and carry the $60$ over to the $51$ to get $111$, which is $55.5$ after division by $2$.
A: My answer is going to be more specific to the calculation you're doing (a + 1/2 * a), so if you have the pace 7:41 and you want to find 7:41 + 1/2 * 7:41.
First you do 7/2 = 3.5, and add it to the original time 7:41+3.5 = 10.5:41, then if necessary, normalize the .5 to 10:71
Second you add the seconds 10:71 + 41/2 = 10:91. 
Finally, normalize it to 11:31.
An example run of it in your head:
A    B    C
7    ...  ... (read the minute from the panel)
7    3.5  ... (divide by 2)
10.5 ...  ... (add it to the minute)
10.5 41   ... (read the panel again for the second)
10   71   ... (normalize the .5 by adding 30 to the seconds)
10   71   41  (read the panel again for the second)
10   71   20  (divide by 2)
10   91   ... (add to the seconds)
11   31   ... (normalize) 

This might be easier for some people than doing a base-60 division first as the steps are IMO simpler to work with in (my) head. So the algorithm is basically:


*

*Read the time 

*Add the minute part

*Add the seconds part

