Question: There is a castle shaped like an equilateral triangle. The length of each side of the castle is $200$ meters. Five guards are placed around the perimeter of the castle spaced as far apart as possible. Using the pigeonhole principle, prove that there are always two guards within $100$ meters of each other. You may assume the following theorems are true:
• The line segment in a triangle joining the midpoint of two sides of the triangle is said to be parallel to its third side and is also half of the length of the third side.
• The distance between two points inside an equilateral triangle is less than the side of the triangle.
My attempt: To place guards around the castle, I would start by placing three at the vertices. Then because they are spaced as far apart as possible, the next two would be placed at the midpoints of two sides. Then the guards on the vertices will be 100 meters from the guards on the midpoints and the guards on the midpoints will be 100 meters apart because of the first theorem. Where does the pigeonhole principle come in however?