# $f$ is holomorphic in $\Omega$ such that $|f|$ is harmonic; we need to show that $f$ is constant.

$f$ is holomorphic in $\Omega$ such that $|f|$ is harmonic; we need to show that $f$ is constant.

Let

$$f=u(x,y)+iv(x,y)\Rightarrow |f|=\sqrt{u^2+v^2}\quad \rm{and}\quad \nabla^2|f|=0$$ right?

Also I have $u_x=v_y, v_x = -u_y$

$$\nabla^2 = {\partial^2\over \partial x^2}+{\partial^2\over \partial y^2},$$

so as $\nabla^2|f|=0$ we get

$$u_{xx}+u_{yy}+v_{xx}+v_{yy}=0$$

So now could any one show me how to proceed?

• Try showing that $\Delta|f| = |f|^{-1}\left|\frac{\partial f}{\partial z}\right|^2$. The result follows quickly from there. – Cameron Williams Jun 20 '13 at 5:48

## 1 Answer

Try to complete the proof using the following hints:

1) If $f$ is nonzero in a neighborhood $U$ then $\log f$ exists.

2) $\log|f|$ is harmonic.

3) If $g$ is a harmonic function such that $\log|g|$ is also harmonic then $g$ is constant.

4) $f$ holomorphic and $|f|$ constant in a neighborhood implies $f$ is constant.