What happens to $w=\frac{x^2y^3}{z^4}$ , if $x,y,z$ increase by $\%1$ , $\%2$ , $\%3$ respectively? If $x,y,z$ increase by $\%1$ , $\%2$ , $\%3$ respectively , then $w=\dfrac{x^2y^3}{z^4}$ ............. approximately.
$1)\ \%\ 3\text{ decrease}$
$2)\  \%\ 4\text{ decrease}$
$3)\ \%\ 3\text{ increase}$
$4)\ \%\ 4\text{ increase}$
I denote the new $w$ by $w'$,
$$w'-w=\left( \frac{1.01^2.1.02^3}{1.03^4}-1\right)\times w=\left(\frac{101^2\times102^3}{103^4\times100}-1\right)\times w$$
From here should I evaluate $\dfrac{101^2\times102^3}{103^4\times100}-1$ by hand (calculator is not allowed) or there is a quicker method to get to the correct answer?
 A: A rule of thumb: $1.001^n$ is about $1.00n$. More precisely, $(1+\alpha)^n\approx 1+n\alpha$ for small $\alpha$. This helps with a lot of estimation problems.
A: Dividing the numerator and denominator both by $100^5$ gives $$\frac{1.01^2 . 1.02^3}{1.03^4} -1$$ Now, we use $(1+x)^n=1+nx$ for $x<<1$.
Using this, we get $(1+0.02)(1+0.06)(1-0.12)-1$ which is approximately equal to $-0.04$.
A: We can use approximations here
$$w=\dfrac{x^2y^3}{z^4}$$
Taking $\ln()$ on both sides
$$\ln w=2\ln x+3\ln y-4\ln z$$
Differentiating both side gives
$$\displaystyle\frac{dw}{w}=2\frac{dx}{x}+3\frac{dy}{y}-4\frac{dz}{z}$$
Substituting values
$$\displaystyle\frac{dw}{w}=2\frac{0.01x}{x}+3\frac{0.02y}{y}-4\frac{0.03z}{z}$$
$$\displaystyle\frac{dw}{w}=0.02+0.06-0.12=-0.04$$
Therefore $$\displaystyle\frac{dw}{w}*100=-4\text{%}$$
Hence there's a decrease of $4\text{%}$ in $w$
A: You can use partial elasticities, also know as condition numbers:
\begin{align*}
\varepsilon_w \approx & \frac{x w'_x}{w} \varepsilon_x+\frac{y w'_y}{w} \varepsilon_y + \frac{z w'_z}{w} \varepsilon_z\\
= & 2\varepsilon_x + 3 \varepsilon_y - 4 \varepsilon_z= 2 + 3\times 2-4 \times 3 = -4
\end{align*}
So, the answer is an approximate decreasing by $\text{4%}$.
This comes from Taylor's formula:
\begin{align*}
f(\tilde x) \approx f(x) + f'(x)(\tilde x -x) \Rightarrow  \\
f(\tilde x) - f(x) \approx f'(x)(\tilde x -x) \Rightarrow \\
\frac{f(\tilde x) - f(x)}{f(x)} \approx  \frac{f'(x)(\tilde x -x)}{f(x)} \Rightarrow\\
\frac{f(\tilde x) - f(x)}{f(x)} \approx  \frac{xf'(x)}{f(x)} \frac{\tilde x -x}{x}
\end{align*}
