15
$\begingroup$

Let $RP^n$ be the $n$-dim real projective space. I have the following four questions.

  1. What is the so called standard metric on $RP^n$?
  2. More generally, consider a metric space $M$ with an equivalent relation ~. Then there is a natural way to define a (pseudo)metric on the quotient space $M$\~. See Why are quotient metric spaces defined this way? for details. It seems to me that if we regard $RP^n$ as the quotient from $R^n$\{0}, then the induced pseudo metric is not a metric, however, if we regard $RP^n$ as the quotient from $S^n$, then the induced pseudo metric is a metric. Am I correct? Is there a contradiction?
  3. What is the standard measure on $RP^n$?
  4. How to in general define a measure on the quotient of a measure space? (similar to question 2)

Thank you for reading and thinking for my long questions. I put them in a logical order, however, I'm mostly interested in the third question. If you can't help me with all the questions, please try Q3 first.

$\endgroup$

1 Answer 1

15
$\begingroup$
  1. Apparently you ask about metric as two-point function, not about Riemannian metric in the projective space. The answer (consistent with the Riemannian metric) is: angle between lines through the origin in $\mathbb R^{n+1}$ (which represent points in $\mathbb RP^n$). The diameter of the space is $\pi/2$.

  2. Correct on both counts. Using the Euclidean metric on $\mathbb R^{n+1}\setminus \{0\}$ and collapsing along lines leads to a disaster: the quotient pseudo-metric is identically zero, because the Euclidean distance between any two lines through the origin is zero. This issue does not arise with $S^n/\{\pm I\}$, whether we use the restriction (chord) metric on $S^n$ or the intrinsic (arc) metric. The latter choice is more natural, and yields the metric described in 1.

  3. Pushing things from $S^n$ to $S^n/\{\pm I\}$ by the quotient map is a convenient and natural way to equip $\mathbb RP^n$ with various structures, including the measure. The pushforward of normalized Lebesgue measure on $S^n$ gives the standard probability measure on $\mathbb RP^n$.

  4. First, try pushing forward by the quotient map. Sometimes this does not work: for example, pushing the Lebesgue measure by the quotient map $\mathbb R\mapsto \mathbb R/\mathbb Z$ we get something ugly (which gives infinite measure to every nontrivial arc of the circle). In such a case, consider restricting the measure to a fundamental domain first.

$\endgroup$
2
  • $\begingroup$ Thank you so much for your answers. I want make sure I understood what you mean in Q3. So a set $E$ in $RP^n$ is measurable if the inverse of $E$ under the projection map is measurable, and the measure of $E$ is defined as the measure of its inverse. Am I right? $\endgroup$
    – Tony B
    Commented Jun 17, 2013 at 15:02
  • $\begingroup$ @user16418 Yes, this is how pushforward measure works. Except we usually want a more concrete description of measurable sets. Clearly, the preimage of a Borel set under this projection is also Borel. This gives a Borel measure on the projective space, which we may decide to complete in the usual way. $\endgroup$ Commented Jun 17, 2013 at 15:09

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .