Circular Motion, Vectors and Elasticity My Doubts: Elastic modulus should be in $$N/m^2$$ but here it is in Newtons only is this correct or they just mean here $$k=30 N/m$$ ? What do you want to say about $$\lambda = 30 N$$ ?

Do you think my equations are correct to solve for correct answer

My Try:

Let $$x$$ be the elongation, so we have $$T\cos\theta=mg$$ $$T\sin\theta=m\omega^2 r \;\;\;,\;\;\;r=(l+x)\sin\theta$$ $$T=kx$$

Using these three equations I can solve for $$\theta\;\;,\;\; T$$.

Is this correct ?

• very good that you wrote $r=l+x \sin \theta$ , if it was me , I'd have completely missed that lol. However, the equations look ok to me. Aug 5 '21 at 8:28
• thanks , i just want to know about lambda i think it is not standard notation Aug 5 '21 at 8:29

I suspect that the author defines elastic modulus here as $$\frac{\text{tension in the string}}{\text{relative extension}}\\=\text{tension in string}\times\frac{\text{original length}}{\text{elongation}},$$ which has units Newtons.